prove that if a line is drawn parallel two sides in district point. the other two sides are divided in same ratio.
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Step-by-step explanation:
Given:
DE∣∣BC
To prove that:
AE
EC
=
AD
BD
Proof:
∠AED=∠ACB Corresponding angles
∠ADE=∠ABC Corresponding angles
∠EAD is common to both the triangles
⇒ΔAED∼ΔACB by AAA similarity
⇒
AE
AC
=
AD
AB
⇒
AE
AE+EC
=
AD
AD+BD
⇒
AE
EC
=
AD
BD
Hence proved
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