prove that if a number is tripled then it's cube is 27 times the cube of the given number
question.26
plz also give an explaination.
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Answered by
1
Solution :-
Let us assume that the original number = 'x'
Its cube = (x)³
= x³
If the original number is tripled then the new number = 3*x
= 3x
Cube of the new number = (3x)³
= 3x*3x*3x
= 27x³
Therefore,
Cube of the original number : Cube of the new number which is tripled
⇒ 1 : 27
Hence, the cube of the new number is 27 times the cube of the original number.
Hence proved
Let us assume that the original number = 'x'
Its cube = (x)³
= x³
If the original number is tripled then the new number = 3*x
= 3x
Cube of the new number = (3x)³
= 3x*3x*3x
= 27x³
Therefore,
Cube of the original number : Cube of the new number which is tripled
⇒ 1 : 27
Hence, the cube of the new number is 27 times the cube of the original number.
Hence proved
Answered by
1
step by step explanation
Let the number be x so it's cube is (x)^3
Now by tripling it the number becomes 3x
and it's cube will be (3x)^3 = 3x × 3x × 3x = 27(x)^3
now u can clearly see that 27(x)^3 is 27 times of (x)^3
hope it helps
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