Prove that if a number is tripled then its cube is 27 times the cube of the given number.
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Answers
Answered by
2
heya........
Solution :-
Let us assume that the original number = 'x'
Its cube = (x)³
= x³
If the original number is tripled then the new number = 3*x
= 3x
Cube of the new number = (3x)³
= 3x*3x*3x
= 27x³
Therefore, Cube of the original number : Cube of the new number which is tripled
⇒ 1 : 27
Hence, the cube of the new number is 27 times the cube of the original number.
Hence proved
Answer.
tysm............@kundan
Solution :-
Let us assume that the original number = 'x'
Its cube = (x)³
= x³
If the original number is tripled then the new number = 3*x
= 3x
Cube of the new number = (3x)³
= 3x*3x*3x
= 27x³
Therefore, Cube of the original number : Cube of the new number which is tripled
⇒ 1 : 27
Hence, the cube of the new number is 27 times the cube of the original number.
Hence proved
Answer.
tysm............@kundan
aadi93:
thanks
Answered by
3
Let,
Any number = x
=================
When x tripled, then cubed,
=> (3x)³
=> (3³ × x³)
=> (27 × x³)
=> 27x³
_______________,,
Hence, proved.
I hope this will help you
-by ABHAY
Any number = x
=================
When x tripled, then cubed,
=> (3x)³
=> (3³ × x³)
=> (27 × x³)
=> 27x³
_______________,,
Hence, proved.
I hope this will help you
-by ABHAY
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