prove that,if a perpendicular is drawn from the centre of a circle to chord,it bisects the chord.
Answers
Answered by
2
Answer:
Let O be the centre of the circle. Let OA and OB be the radius of the circle. AB is a chord of the circle such that OX⊥AB. ... Since AX is equal to BX, so the perpendicular from the centre of the circle bisects the chord at AB.
Answered by
0
Answer:
Step-by-step explanation:
Attachments:
Similar questions