Question

prove that if an angle in the triangle is greater than the sum of other two sides of the triangle the following triangle is an obtuse angled triangle

Answer 1

Heya frnd!!!
Here's ur solution...hope this helps u... ☺☺☺

Given: ᐃABC

∠A > ∠B + ∠C

 

∠A + ∠B + ∠C = 180° Sum of the angles of a triangle.

∠B + ∠C < ∠A Reversal property of the given inequality

∠A > 180° - ∠A differences of unequals subtracted from equals

are unequal in the reverse order.

∠A + ∠A > 180° Adding ∠A to both sides (adding =s to =s)

2∠A > 180² 1+1=2

∠A > 90° Equals divided by equals

 

ᐃABC is an obtuse triangle It has an angle > 90°

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