prove that if an angle in the triangle is greater than the sum of other two sides of the triangle the following triangle is an obtuse angled triangle
Answers
Answered by
1
Heya frnd!!!
Here's ur solution...hope this helps u... ☺☺☺
Given: ᐃABC
∠A > ∠B + ∠C
∠A + ∠B + ∠C = 180° Sum of the angles of a triangle.
∠B + ∠C < ∠A Reversal property of the given inequality
∠A > 180° - ∠A differences of unequals subtracted from equals
are unequal in the reverse order.
∠A + ∠A > 180° Adding ∠A to both sides (adding =s to =s)
2∠A > 180² 1+1=2
∠A > 90° Equals divided by equals
ᐃABC is an obtuse triangle It has an angle > 90°
#stay♡happy
Here's ur solution...hope this helps u... ☺☺☺
Given: ᐃABC
∠A > ∠B + ∠C
∠A + ∠B + ∠C = 180° Sum of the angles of a triangle.
∠B + ∠C < ∠A Reversal property of the given inequality
∠A > 180° - ∠A differences of unequals subtracted from equals
are unequal in the reverse order.
∠A + ∠A > 180° Adding ∠A to both sides (adding =s to =s)
2∠A > 180² 1+1=2
∠A > 90° Equals divided by equals
ᐃABC is an obtuse triangle It has an angle > 90°
#stay♡happy
Similar questions