Prove that if an integer is a perfect square and a perfect cube, simultaneously, then it is either of the form 7k or 7k+1
Answers
Answered by
1
bq/r yhrn
7k 7k+1 are cube 343 k or 343k+1.
7k 7k+1 are cube 343 k or 343k+1.
Answered by
0
Answer:
giving the answer
Step-by-step explanation:
it is of advanced level.
good.
you are solving these all
Similar questions