Prove that if chords of a circles subtend equal angles at their center , then the chords are equal.
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here is ur answer..
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given : B=A=90
to prove : BP=AP
proof : in AOP and BOP
OAP=OBP(90each)
OP=OP(common)
AO=BO(radii)
AOP= BOP(by RHS)
BP=AP(by cpct)
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