prove that if chords of congruent circles subtend equal angles at their centers then the chords are equal
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Step-by-step explanation:
let the two circles with centre O and P are congruent circles, therefore their radius will be equal.
given: AB and CD are the chords of the circles with centres O and P respectively.
∠AOB=∠CPD
TPT: AB=CD
proof:
in the ΔAOB and ΔCPD
AO=CP=r and OB=PD=r
∠AOB=∠CPD
therefore by SAS congruency, ΔAOB and ΔCPD are congruent triangle.
therefore AB=CD
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