Question

prove that if chords of congruent circles subtend equal angles at their centers, then chords are equal ​

Answer 1

Answer:

In △AOB and △PXQ

AO=PX [Radius of congruent circles are equal]

∠AOB=∠PXQ [Given]

BO=QX [Radius of congruent circles are equal]

△AOB≅△PXQ [SAS congruence rule]

∴AB=PQ [CPCT]

Hence proved

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