prove that if chords of congruent circles subtend equal angles at their centers, then the cords are equal.
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Answer:
In △AOB and △PXQ
AO=PX [Radius of congruent circles are equal]
∠AOB=∠PXQ [Given]
BO=QX [Radius of congruent circles are equal]
△AOB≅△PXQ [SAS congruence rule]
∴AB=PQ [CPCT]
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hlo answer is given in the pic ☺️
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