Question

prove that if chords of congruent circles subtend equal angles at their centers, then the cords are equal. ​

Answer 1

Hope it helps u Sonam........

Answer 2

Answer:

Given -

two congruent circles

${c}^{1} and \: {c}^{2}$

$ab \: is \: the \: chord \: of {c}^{1}$

Prove -

In ∆AOB ∆PXQ

AO = PX

angle AOB = Angle PXQ

BO = QX

∆AOB = ∆PXQ

so AB = PQ