Question

prove that if chords of congruent circles subtend equal angles at their centers then the chords are equal ​

Answer 1

Step-by-step explanation:

In △AOB and △PXQ

AO=PX [Radius of congruent circles are equal]

∠AOB=∠PXQ [Given]

BO=QX [Radius of congruent circles are equal]

△AOB≅△PXQ [SAS congruence rule]

∴AB=PQ [CPCT]