Prove that if chords of congruent circles subtend equal angles at their centres, then the chords are equal.
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Answered by
0
Answer:
Step-by-step explanation:
AB = CD i.e. two equal chords.
To Prove
AB = CD
Proof
From ΔAOB and ΔCOD,
OA = OC and OB = OD (Radii of circle)
∠AOB = ∠DOC
So, by SAS congruency,
ΔAOB ≅ΔCOD
∴ By CPCT we get
AB=CD
Hence proved
Answered by
0
Answer:
In △AOB and △PXQ
AO=PX [Radius of congruent circles are equal]
∠AOB=∠PXQ [Given]
BO=QX [Radius of congruent circles are equal]
△AOB≅△PXQ [SAS congruence rule]
∴AB=PQ [CPCT]
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