prove that if chords of congruent circles subtend equal angles at their Centre then the chords are equal
Answers
Answered by
4
hope this will help u.
plz mark as brainliest
plz mark as brainliest
Attachments:
Answered by
6
Statement : If the angle subtended by the chords of a circle at the centre are equal, then the chords are equal.
Given : Two chords PQ and RS of a circle
C (O , r ), such that ∠POQ = ∠ROS.
To prove : PQ = R
Proof :
In ΔPOQ and ΔROS,
OP = OQ = OR = OS = r [radii of same circle]
∠POQ = ∠ROS [Given]
ΔPOQ ≅ ΔROS [ SAS ]
PQ = RS [C. P. C. T]
Hence, If the angle subtended by the chords of a circle at the centre are equal, then the chords are equal.
Given : Two chords PQ and RS of a circle
C (O , r ), such that ∠POQ = ∠ROS.
To prove : PQ = R
Proof :
In ΔPOQ and ΔROS,
OP = OQ = OR = OS = r [radii of same circle]
∠POQ = ∠ROS [Given]
ΔPOQ ≅ ΔROS [ SAS ]
PQ = RS [C. P. C. T]
Hence, If the angle subtended by the chords of a circle at the centre are equal, then the chords are equal.
Attachments:
Similar questions