prove that if chords of congruent circles subtend equal angles at the centre then the chords are equal
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If the radius of two circles is equal then they are called congruent.
So in given figure
In triangle ABO & PQO
OA=OP(radii)
Angle AOB=Angle POQ(given)
OB=OQ(radii)
By SAS
Triangle ABO Is congruent to PQO
By CPCT
AB=PQ
Hence, proved
If the radius of two circles is equal then they are called congruent.
So in given figure
In triangle ABO & PQO
OA=OP(radii)
Angle AOB=Angle POQ(given)
OB=OQ(radii)
By SAS
Triangle ABO Is congruent to PQO
By CPCT
AB=PQ
Hence, proved
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