Question

prove that if chords of congruent circles subtend to equal angles at the centre then the chords are equal​

Answer 1

Answer:

Step-by-step explanation:

If the radius of two circles is equal then they are called congruent.

So in given figure

In triangle ABO & PQO

OA=OP(radii)

Angle AOB=Angle POQ(given)

OB=OQ(radii)

By SAS

Triangle ABO Is congruent to PQO

By CPCT

AB=PQ

Hence, proved.

#Pari here...

Answer 2

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If the radius of the two circles is equal then they are congruent.

So in the given figure,

In triangle ABO & PQO

OA = OP (radii)

Angle AOB = Angle POQ (given)

OB = OQ (radii)

By SAS

Triangle ABO is congruent to PQO

By CPCT

AB = PQ

Hence, Proved

hope it's help you