Question

prove that if chords of cugruent circle subtend equal angles at their centre, then the chords are equal​

Answer 1

Step-by-step explanation:

In ∆AOB and ∆PXQ

AO = PX. [Radius of congruent circles are equal]

angleAOB = anglePXQ (Given)

BO = QX [Radius of congruent circles are equal]

∆AOB≈∆PXQ [SAS congruence rule]

AB = PQ. [CPCT]