Question

Prove that if "Equall Chords of a Cicle subtend equal
angles at the Centre
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Answer 1

Step-by-step explanation:

it's actually very easy....

I don't have notebook now so can explain only via text..

Okay follow the steps:-

1. Draw a round circle (well circle is always round lol)

2. Draw 2 chords in different segments of circle ( I mean opposite segments or one in upper and other in bottom segment)

3. Since the equal chords are in the same circle it's very easy. Let the equal chords be AB and CD and O be the centre of circle.

4. Join OA, OB, OC and OD.

5. Now, two triangles are formed namely Triangle AOB and COD.

6. In triangle AOB and COD,

AB = CD ( given)

OA = OC ( radii of same circle)

OB = OD ( radii of same circle)

So, triangle AOB is congruent to triangle COD.( By S.S.S)

Also, Angle AOB = Angle COD ( By C.P.C.T)

Hence, proved equal chords ( AB = CD) subtend equal angles ( AOB = COD) at the centre O.

Hope it helps

Answer 2

Hope you will understand the answer