prove that if one angle of a triangle is equal to the sum of other two triangle then the triangle is right angle
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Answered by
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Let the larger angle be= a
small angles be = b, c
1. a= b+c
a+b+c=180°
acc to eq 1
2(c+b) = 180°
c+b = 90°
c+b = a
therefore
one angle is 90° i.e a.
Hence proved.
hope this helps. :)
mark it the brainiest pls.
small angles be = b, c
1. a= b+c
a+b+c=180°
acc to eq 1
2(c+b) = 180°
c+b = 90°
c+b = a
therefore
one angle is 90° i.e a.
Hence proved.
hope this helps. :)
mark it the brainiest pls.
lakshikaarora11:
ok
if the measure of an angle is 3 the measure of its supplementary angle then find the one measure of angle
reply me
post this as question
please
separately
yes
what are your mean
I can't understand what you're saying
post this question separately like you do usually. donot post here
Answered by
2
It is given one angle of a triangle is equal to the other two
let ,first angle as angle A ,second angle as angle B and third angle as angle C
According to the question,
angle A=angle B + angle C
we know that the sum of the angels of a triangle is 180°.
angle A+angle B +angle C=180°
angleA+angleA=180
angle 2A=180
angle A=180/2
=90
hence triangle is right angled.
let ,first angle as angle A ,second angle as angle B and third angle as angle C
According to the question,
angle A=angle B + angle C
we know that the sum of the angels of a triangle is 180°.
angle A+angle B +angle C=180°
angleA+angleA=180
angle 2A=180
angle A=180/2
=90
hence triangle is right angled.
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