prove that if side of a triangle is produced the exterior angle so formed is equal to the sum of interior angle
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let in triangle ABC, BC is produced to E
therefore the exterior angle formed is ∠ ACE
we know that,
A+B+C=180
∠C=180-(A+B)
and ∠ ACB+∠ACE=180 (Because linear pair)
therefore,
∠C+∠ ACE=180
180-(A+B)+∠ACE=180
∠ACE=A+B
exterior angle is equal to sum of opp interior angles
therefore the exterior angle formed is ∠ ACE
we know that,
A+B+C=180
∠C=180-(A+B)
and ∠ ACB+∠ACE=180 (Because linear pair)
therefore,
∠C+∠ ACE=180
180-(A+B)+∠ACE=180
∠ACE=A+B
exterior angle is equal to sum of opp interior angles
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