Question

Prove that if the base of an isosceles triangle is produced at both ends, the exterior angles so formed are equal to each other.

Answer 1

Answer:

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let ab = bc of isosceles triangle

opposites angle of opposite sides are equal.

thus angle abc = acb

by extending ab to p and ac to q

angle abc + cbp = 180

and angle acb + bcq = 180

by equating both eqns.

abc + cbq =acb + bcq

since abc = acb

cbq = bcq

hence proved