Prove that,if the bisector of angle BAC of triangle ABC is perpendicular to side BC,then triangle ABC is an isosceles triangle.
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In ΔADB and ΔADC
∠BAD=∠CAD (AD id the bisector of ∠BAC)
∠BAD=∠CDA=90
∘
(Given)
AD=DA (Common)
By ASA test of congruency
ΔADB≅ΔADC
∴∠B=∠C (corresponding angles of congruent triangles)
If two angles of a triangle are equal, then the triangle is said to be a isosceles triangle
Step-by-step explanation:
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