prove that if the diagonals of a parallelogram are equal then it is a rectangle
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ABCD be parallelogram. The parallelogram law states : sum of squares of sides = sum of squares of diagonals. a, b are sides. c, d are diagonals. here c = d.
2 a² + 2 b² = c² + d² = 2 c² => a² + b² = c²
=> a and b are at right angles. => rectangle.
2 a² + 2 b² = c² + d² = 2 c² => a² + b² = c²
=> a and b are at right angles. => rectangle.
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Answer:ABCD be parallelogram. The parallelogram law states : sum of squares of sides = sum of squares of diagonals. a, b are sides. c, d are diagonals. here c = d.
2 a² + 2 b² = c² + d² = 2 c² => a² + b² = c²
=> a and b are at right angles. => rectangle.
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