Prove that if the momentum of two bodies is same then the velocity of lighter body will be more than the velocity of heavier body.
SamuraiAdnan:
I want to know which will have higher velocity,not kinetic energy.
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Kinetic energy = (1/2)mv^2
Multiply left hand side of equation by m,
KE = m^2×v^2/(2×m)
KE = (m×v)^2/(2×m)
Momentum = p =m×v
KE = p^2/(2×m)
Momentum is same therefore KE is inversely proportional to mass. Therefore lighter body has more kinetic energy.
Hope this will help
Multiply left hand side of equation by m,
KE = m^2×v^2/(2×m)
KE = (m×v)^2/(2×m)
Momentum = p =m×v
KE = p^2/(2×m)
Momentum is same therefore KE is inversely proportional to mass. Therefore lighter body has more kinetic energy.
Hope this will help
I want to know the wh8ch will have more velocity not kinetic energy.
so u can make out that it will have high V
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