prove that if three parallel lines are intersected by two transversal are proportional
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three parallel lines l,m,n which are cut by the transversals AB and CD in P, Q, R and E ,F,G respectively We shall prove,
QR
PQ
=
FG
EF
Draw PL∥CD meeting the lines m and n In M and L m respectively PROOF Since PE∥MF and PM∥EF ∴ PMFE is a prallelogram ⇒ PM = EF ....(i) (Opposite side of a ∥
gm
are equal ) Also MF∥lgandML∥FG Therefore MLGF is a parallelogram ML = FG ......(ii) (Opposite side of a ∥
gm
are equal ) Now in △PRLQM∥RL
QR
PQ
=
ML
PM
[Using Basic proportionality Theorem] or
QR
PQ
=
FG
HOPE IT HELPS YOU......
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hope i do not help u tgx for free 5 points
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