Question

prove that if two sides of a triangle are unequal the greater side has the greater angle opposite to it​

Answer 1

Answer:

For example take a right angled triangle ABC

Here side AC is greater than AB because,

According to Pythagoras theorem

AC² = AB² + BC²

Angle opposite to side AB is angle ACB and for side AC it is ABC which is a right angle I.e., 90°

Angle ACB is smaller than Angle ABC I.e.,<90°

Hence roved that if two sides of a triangle are unequal the greater side has the greater angle opposite to it