prove that if x and y are both add positive integers, then x square + y square is even but not divisible by 4
Ayakashi:
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I suggest writing them as 2α+1 and 2β+1, where α and β could be any
natural number, odd or even. Then we could proceed by writing
x² + y² as
(2α+1)² + (2β+1)²
(4α² + 4α + 1) + (4β² + 4β +1)
4(α² + β² + α + β) + 2
So x² + y² is 2 more than a multiple of 4. Therefore it must be even, but can never be a multiple of 4 itself. See if you can prove this: if x and y are even numbers not divisible by 4, then x² + y² must be divisible by 8, but not 16.
(2α+1)² + (2β+1)²
(4α² + 4α + 1) + (4β² + 4β +1)
4(α² + β² + α + β) + 2
So x² + y² is 2 more than a multiple of 4. Therefore it must be even, but can never be a multiple of 4 itself. See if you can prove this: if x and y are even numbers not divisible by 4, then x² + y² must be divisible by 8, but not 16.
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