prove that if x and y are odd positive integers;x>y then x^2-y^2 divisible by 4
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Since x is odd, then x = 2a + 1 for some integer a.
Since y is odd, then y = 2b + 1 for some integer b.
Notice x>y means a>b, but that is actually not important here!
In terms of a and b, we have
x² - y²
= ( 2a + 1 )² - ( 2b + 1 )²
= ( 4a² + 4a + 1 ) - ( 4b² + 4b + 1 )
= 4 ( a² + a + b² + b )
which is divisible by 4 since (a²+a+b²+b) is an integer.
Hope this helps!
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