Question

Prove that if x=logbc base a , y=logca base b, logab base c then 1/x+1 + 1/y+1 + 1/z+1 = 1​

Answer 1

Answer:

if x= log -a (bc),log b (ca), and z=log c(ab) then 1/(x+1)+1(y+1)+1(z+1)