Prove that ifx and y are odd positive integers, then x2+y2 is even but not visible by 4.
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Suppose, the two odd numbers are x=2n-1 and y=2n+1.
Now, according to the question:
(2n-1)^2+(2n+1)^2
Expand it using the basic algebric formula i.e.
(a+b)^2=a^2+b^2+2ab and (a-b)^2=a^2+b^2-2ab
We get,
(2n-1)^2+(2n+1)^2=4n^2+4n+1+4n^2-4n+1
8n^2+2=2(4n^2+1)
Therefore, the above expression is divided by 2 means x^2+y^2 is even but not divisible by 4.
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