Question

Prove that in 2 concwntric circles,the chord of the larger circle,which touches the smaller circle,is bisected at the point of contact.

Answer 1

ANSWER IS GIVEN IN THE ATTACHMENT 

Answer 2

given = Two circles with the same centre O and AB is a chord of the larger circle touching the smaller circle at C .
to prove - AC = BC
construction - Join OC

AB is a tangent to the smaller circle at the point C and OC is the radius through C .
but,the perpendicular drawn from the centre of a circle to a chord bisects the chord .
hence , AC = BC