prove that in a convex hexagon sum of its exterior angles is half of the sum of its interior angles.
Answers
Answered by
0
Answer:
In a hexagon number of sides=6
∴ Sum of interior angles of a hexagon=(2×6−4)×90°=8×90°=720°
Sum of exterior angle of a hexagon =360°
We know 360 = 720/2
Therefore, sum of exterior angles of a hexagon is half the sum of its interior angles (Proved)
Hope it helps!
Please mark as the brainliest answer :)
Similar questions