Prove that in a convex hexagon, the sum of the interior angles is equal to the twice the sum of the sum of the exterior angles.
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Now we also know that in any polygon the sum (Sex) angle is always equal to 3600. Now from equation (1) and (2) we can say that, sum of interior angles is equal to two times the sum of exterior angles. So the sum of all interior angles in a convex hexagon is equal to twice the sum of its exterior angles. Hence Proved.
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