prove that in a parallelogram ABCD are equal
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If — AB ≅ — CD and — BC ≅ — DA , then ABCD is a parallelogram. If both pairs of opposite angles of a quadrilateral are congruent, then the quadrilateral is a parallelogram
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ABCD is a parallelogram.
To prove that AB = CD and AD = BC.
Join the diagonal AC.
In the triangles ABC and CDA:
angleBAC = angleDCA (alternate angles, AB || DC)
angleBCA = angleDAC (alternate angles, AD || BC)
AC = CA (common)
so triangleABC ≡ triangleCDA (AAS)
Hence AB = CD and BC = AD (matching sides of congruent triangles).
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