prove that in a quadrilateral ABCD,perimeter is greater than twice of any side
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Answered by
4
yes exampleis l =4cm
b=3cm
perimeter=24
b=3cm
perimeter=24
Answered by
12
Answer:
The proof is explained step-wise below :
Step-by-step explanation:
For better understanding of the solution, see the attached figure of the problem :
We know that in a triangle sum of two sides is always greater than the third side.
In ΔABC
AB + BC > AC
⇒ AB + BC + CD > AC + CD ......(1)
In ΔADC
AC + CD > AD ........(2)
From (1) and (2)
⇒ AB + BC + CD > AD
⇒ AB + BC + CD + AD > AD + AD
⇒ Perimeter of quadrilateral ABCD > 2 × AD
Similarly , We can prove that
⇒ Perimeter of quadrilateral ABCD > 2 × AB
⇒ Perimeter of quadrilateral ABCD > 2 × BC
⇒ Perimeter of quadrilateral ABCD > 2 × CD
Hence, The perimeter of the quadrilateral ABCD is greater than twice of any side.
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