prove that in a quadrilateral sum of all the angles of a quadrilateral is 360°
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Sum all interior angles of n sides polygon is (n-2)180°
The sum of all interior angles of quadrilateral =(4-2)180°=360°
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the sum of all the angles of a quadrilateral is 360° because a quadrilateral can be divided into two triangles and the sum of all angles of a triangle is 180°
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