prove that in a quadrilateral the sum of all the sides is greater than the sum of its diagnols
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=> AB + BC > AC ➡equation 1
=> BC + CD > BD➡equation 2
=> CD + AD > AC➡equation 3
=> AD + BA > BD ➡equation 4
ADD ALL EQUATION
=> AB + BC + BC + CD + CD + AD + AD + BA > AC + AC + BD + BD
=> 2 (AB + BC + CD + AD) > 2 (AC + BD)
=> AB + BC + CD + AD > AC + BD
Hence , Proved
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