Prove that in a quadrilateral,the sum of exterior angle is 360°
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The sum of all angles in quadrilateral is 360
So each extrior angle is of 90 hve four angles so the sim is 360
So each extrior angle is of 90 hve four angles so the sim is 360
anushka1422:
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Statement :
sum of the angles of quadrilateral is 360°
To Prove :
∠A + ∠B + ∠C + ∠D = 360°
Proof :
In ∆ ABC , m∠4 + m∠5+m∠6 = 180°
[ using angle a property of a triangle]
Also , in ∆ ADC , m∠1 + m∠2+m∠3= 180°
Sum of the measures of ∠A, ∠B , ∠C and ∠D of a quadrilateral
m∠4 + m∠5+ m∠6 + m∠1 + m∠2 +m∠3 = 180°+ 180°
→ ∠A + ∠B + ∠C + ∠D = 360°
Thus , sum of measure of four angles of quadrilateral is 360°.
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