Question

Prove that in a regular hexagon, the sum of all its interior angles is twice the sum of exterior angles formed by producing the sides in the same order.Find the value of each interior and the corresponding exterior angle of the regular hexagon.

Answer 1

Let be 'x' degree the measure of an exterior angle, then the measure of an interior angle is '2x' degree.

Assume that the regular polygon has n sides (or angles).

We know that the sum of the interior angles is n×2x=(n−2)×180 and the sum of exterior angles is 

n×x=360

⇒x=n360

Substituting this value for x in the first equation, we get

nn×2×360=(n−2)×180

⇒4×180=(n−2)×180

⇒4=(n−2)

⇒n=6

Hence, option B is correct.

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Answer 2

Answer:

easy that is ok na that is only the answer