Math, asked by vsb57, 12 days ago

Prove that in a rhombus with an angle of 60°, the shorter diagonal divides
the rhombus into two equilateral triangles.​

Answers

Answered by zaarabarhi
0

Answer:

If one of the diagonals is equal in measure to one of the sides, the rhombus must be formed from two equilateral triangles.

Since, In equilateral triangle each angle is of 60 degree.

therefore, the smaller angles are 60 degrees, and the larger angles must be two times 60 or 120 degrees.

Option B is correct

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