Prove that in a rhombus with an angle of 60°, the shorter diagonal divides
the rhombus into two equilateral triangles.
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if if one of the diagonal is equal in measure to one of the side, the rhombus must be formed from two equivaleral triangles.
since, in equilateral triangle each angle of 60°
therefore, smaller angle are 60° , and the large angle must be two times 60 or 120 degrees .
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