prove that in a right angle triangle if altitude is drawn to the hypotenuse then two triangles formed will be similar to original triangle and to each other
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Step-by-step explanation:
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Given:
The altitude is drawn to the hypotenuse.
To Find:
To prove that in a right angles triangle two triangles formed will be similar to the original triangle and each other.
Solution:
It is given that altitude is drawn to the hypotenuse in a right-angled triangle.
As we know, If the altitude is drawn to the hypotenuse of a right triangle, then the two triangles formed are similar to the original triangle and each other.
Now, draw a line perpendicular to BD and AC.
Then, in ΔABD and ΔABC
ΔADB ≅ ΔABC [ both are congruent because they are 90°]
∠A ≅ ∠A [common angles of the triangle]
Now, by AA similarity criteria
ΔADB ~ΔABC.(i)
Then, in ΔBDC and ΔABC
ΔBDC ≅ ΔABC
BDC ≅ ABC [both 90°]
∠C ≅ ∠C [common angles of a triangle]
Now, again by AA similarity criteria
ADC is similar to ABC ..(ii)
Using (i) and (ii) we get
ΔADB is similar to triangle ΔBDC.
∴ΔADB ~ ΔBDC