prove that in a right angle triangle the length of the median of the hypotenuse is half of the length of the hypotenuse
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Answer:
Given: In ∆PQR, ∠Q = 90°. QD is the median drawn to hypotenuse PR.
Midpoint Theorem on Right-angled Triangle
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To prove: QS = 12PR.
Given: In ∆PQR, ∠Q = 90°. QD is the median drawn to hypotenuse PR.
Midpoint Theorem on Right-angled Triangle
To prove: QS = 12PR.
Construction: Draw ST ∥ QR such that ST cuts PQ at T.
1. In ∆PQR, PS = 12PR. [S is the midpoint of PR].
2.In ∆PQR,
(i) S is the midpoint of PR [Given]
(ii) ST ∥ QR [By construction.]
3.Therefore, T is the midpoint of PQ. [By converse of the Midpoint Theorem.]
4.TS ⊥ PQ. [TS ∥ QR and QR ⊥ PQ]In ∆PTS and ∆QTS ,
5. (i) PT = TQ [From the statement 3.]
(ii) TS = TS [ Common side.]
(iii) ∠PTS = ∠QTS = 90°. [From the statement 4.]
6. Therefore, ∆PTS ≅ ∆QTS. [ By SAS criterion of congruency].
7. PS = QS. [ CPCTC]
Therefore, QS = 12PR. [ Using statement 7 in statement 1.]