Question

prove that in a right angled traingle the altitude from point of intersection is perpendicular sides aleays bisect the hypotenuse ​

Answer 1

Explanation:

In a right-angled triangle, the point of intersection of perpendicular bisectors of sides is the midpoint of the hypotenuse.

Imagine a triangle △ABC.

Let O be the circumcenter, then O can lie on the line BC.

If OB=OC by definition of the circumcenter i.e. O must be the midpoint of the segment BC.

In that case ∠A=90

∘

, since it subtends diameter BC.