Question

Prove that in a Right angled triangle, right angled at B,
sin2 A + cos2A = 1​

Answer 1

Answer:

Step-by-step explanation:

Given, Δ ABC is right angled at C.

Now A+B+C=180

or, A+B=90

 [ Since C=90 ]

or, B=90             ............(i)

Now, sin

A+sin sq. =B=sin sq.

A+sin sq. =90 -A

=sin sq.A+cos sq.A

=1.

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