Question

Prove that in a right angled triangle square of the hypotenuse is equal to sum of the square of the other two sides

Answer 1

according to Pythagoreas theorum it says that the two squares of the short edge lines leaving the long edge of the right angle triangle is equal to the square of the hypotenuse for example ABC is a right angled triangle and given is AB=4cm, BC=3cm and CA=5cm let's verify it now, square of:-
AB=4cm=16
BC=9
CA=25
now let's see what we get
16+9=25 bingo!

Answer 2

the solution is in the photo above
and this is the answer