Question

Prove that in a right angled triangle square of the hypotenuse is equal to sum of the square of other two sides

Answer 1

this is the solution u can also refer ncert class 10 pgno. 146

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Answer 2

Answer:

Let BC be the base = 4 cm

Let AB be the height = 3 cm

Let AC be the hypotenuse with no value

Then,

AB^2 + BC^2 = AC^2   (by Pythagoras Theorem)    

=> 3^2 +4^2=AC^2

=> 9+16=AC^2

=>25=AC^2

=>5^2= AC^2

=>5 cm=AC (by removing the squares)

Now, try to construct it and check whether the measurements are equal.

If it is correct, then your question is proved