Question

prove that, in a right angled triangle 'sum of the square of the perpendicular sides of the triangle is equal to the square of the hypotenuse'.

Answer 1

Answer:

let the names of perpendicular side as be a and b, the name of hypotenuse be c.

Through Pythagoras theorem a square +b square =c square

Step-by-step explanation:

For example let a be 3 cm ,b be 4 cm and we have to find c

therefore 3 square is 9 and

4 square is 16.so 9+16=25 which is 5 square so c = 5cm

Answer 2

Step-by-step explanation:

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