Question

prove that in a right angled triangle the square in the hypoteneous is equal to the sum of the square on the other two sides
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Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

Hi

Construct a right triange right angled at B.

construction: construct a perpendicular BD on side of AC

given: angleB= 90 degrees

to prove: AB2+BC2=AC2

proof: in triangle ABD and tri ABC,

angle A= angle A

angle ADB = angleBDC=90

therefore, triADB is similar to triABC.

which implies AD/AB=AB/AC (sides are in proportion)

which implies AD*AC=AB2 eq1.

Similarly, tri BDC is similar to tri ABC

BC/DC=AB/BC (sides are in proportion)

which implies AC*DC=BC2 eq-2

add 1 and 2

AD.AC=AB2

AD.AC+AC.DC=AB2+BC2

=AC(AD+DC)=AB2+BC2

=AC2=AB2+BC2

Hence proved.

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