Question

Prove that in a right angled triangle the square of the hypotenuse is double the smallest side

Answer 1

Answer:

Step-by-step explanation:

Let acute angles A and C of a right angled triangle ABC are x and 2x degrees.

Accordingly:-

x+2x+90=180. or 2x=90°. =>. x=30°

or. A=30°. , C =60° and. B=90°. . Thus ,

longest side (hypotenuse) is AC and shortest side is BC . by Sine rule:-

AC/sin 90° = BC/sin 30°

AC/1= BC/(1/2)

or. AC= 2.BC. Proved.